0=(-16x^2)+220

Solution for 0=(-16x^2)+220 equation:

0=(-16x^2)+220

We move all terms to the left:

0-((-16x^2)+220)=0

We add all the numbers together, and all the variables

-((-16x^2)+220)=0


We calculate terms in parentheses: -((-16x^2)+220), so:

(-16x^2)+220

We get rid of parentheses

-16x^2+220

Back to the equation:

-(-16x^2+220)


We get rid of parentheses

16x^2-220=0

a = 16; b = 0; c = -220;
Δ = b2-4ac
Δ = 02-4·16·(-220)
Δ = 14080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14080}=\sqrt{256*55}=\sqrt{256}*\sqrt{55}=16\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{55}}{2*16}=\frac{0-16\sqrt{55}}{32}
=-\frac{16\sqrt{55}}{32}
=-\frac{\sqrt{55}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{55}}{2*16}=\frac{0+16\sqrt{55}}{32}
=\frac{16\sqrt{55}}{32}
=\frac{\sqrt{55}}{2}
$